`
Connect With Us!
IOS Store
Share Thread:
 
Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
A new 1/1 for me! And a little help needed...
#11

RE: A new 1/1 for me! And a little help needed...
(08-09-2017, 03:40 PM)jonathani Wrote: I'm not saying anyone would ever do this, but how hard would it be to stamp cards with a "1/1" in gold foil, hypothetically asking? Sometimes I think, "I just saw that card a couple days ago!" on an auction site, but the "1/1" is in a different place--per my memory. I wish the factory would cover it with something that was unique and harder to find than a stamp at a craft store.
I hear ya. That's why, before I buy a card or even make an offer, I do my research. I check Worthpoint, I check COMC, and then I check Beckett. It was easy, because Beckett lists this as the "xfractor 1/1". It wouldn't be hard at all to stamp a base card with a 1/1, but that's why I do my research first Wink.
Steven Jackson Collection
Total cards = 1,648
Autos = 376
Patches = 341
1/1’s = 94
Full rainbows = 24!
Reply
#12

RE: A new 1/1 for me! And a little help needed...
Here is the rest of the rainbow...still looking for the Red and getting a Pigskin Refractor

2009 Steven Jackson Topps Finest Refractor

[Image: 5144yw4s.jpg]

2009 Steven Jackson Topps Finest Blue Refractor #d 102/429

[Image: 5545825r.jpg][Image: p4661wb3.jpg]

2009 Steven Jackson Topps Finest Green Refractor #d 177/199

[Image: wy48bcb3.jpg][Image: wa629y8a.jpg]
2009 Steven Jackson Topps Finest Gold Refractor #d 02/75

[Image: m0a1630x.jpg][Image: 0bc5986b.jpg]

2009 Steven Jackson Topps Finest Pigskin Gold Refractor #d 22/25

[Image: 89g0z600.jpg][Image: j51752x7.jpg]

Looks great with its big brother!

2009 Steven Jackson Topps Finest Xfractor 1/1

[Image: 363942e8.jpg][Image: h1qfupb7.jpg]
Steven Jackson Collection
Total cards = 1,648
Autos = 376
Patches = 341
1/1’s = 94
Full rainbows = 24!
Reply
#13

RE: A new 1/1 for me! And a little help needed...
Very nice!
Reply


Forum Jump:


Users browsing this thread: 1 Guest(s)